Solve for x, y, z
x=-3
y=1
z=1
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x=-2y-3z+2
Solve x+2y+3z=2 for x.
2\left(-2y-3z+2\right)+3y-z=-4 -\left(-2y-3z+2\right)+y+2z=6
Substitute -2y-3z+2 for x in the second and third equation.
y=-7z+8 z=-\frac{3}{5}y+\frac{8}{5}
Solve these equations for y and z respectively.
z=-\frac{3}{5}\left(-7z+8\right)+\frac{8}{5}
Substitute -7z+8 for y in the equation z=-\frac{3}{5}y+\frac{8}{5}.
z=1
Solve z=-\frac{3}{5}\left(-7z+8\right)+\frac{8}{5} for z.
y=-7+8
Substitute 1 for z in the equation y=-7z+8.
y=1
Calculate y from y=-7+8.
x=-2-3+2
Substitute 1 for y and 1 for z in the equation x=-2y-3z+2.
x=-3
Calculate x from x=-2-3+2.
x=-3 y=1 z=1
The system is now solved.
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