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2\left(y-1\right)\times \frac{3}{2}-2\times 3=2\left(y-1\right)
Consider the second equation. Variable y cannot be equal to 1 since division by zero is not defined. Multiply both sides of the equation by 2\left(y-1\right), the least common multiple of 2,y-1.
\left(2y-2\right)\times \frac{3}{2}-2\times 3=2\left(y-1\right)
Use the distributive property to multiply 2 by y-1.
3y-3-2\times 3=2\left(y-1\right)
Use the distributive property to multiply 2y-2 by \frac{3}{2}.
3y-3-6=2\left(y-1\right)
Multiply -2 and 3 to get -6.
3y-9=2\left(y-1\right)
Subtract 6 from -3 to get -9.
3y-9=2y-2
Use the distributive property to multiply 2 by y-1.
3y-9-2y=-2
Subtract 2y from both sides.
y-9=-2
Combine 3y and -2y to get y.
y=-2+9
Add 9 to both sides.
y=7
Add -2 and 9 to get 7.
x+\frac{1}{7-1}=2
Consider the first equation. Insert the known values of variables into the equation.
x+\frac{1}{6}=2
Subtract 1 from 7 to get 6.
x=2-\frac{1}{6}
Subtract \frac{1}{6} from both sides.
x=\frac{11}{6}
Subtract \frac{1}{6} from 2 to get \frac{11}{6}.
x=\frac{11}{6} y=7
The system is now solved.