Solve for r, y
y=-48
r=0
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y=8\left(-6\right)
Consider the second equation. Multiply both sides by -6, the reciprocal of -\frac{1}{6}.
y=-48
Multiply 8 and -6 to get -48.
r-\frac{1}{6}\left(-48\right)=8
Consider the first equation. Insert the known values of variables into the equation.
r+8=8
Multiply -\frac{1}{6} and -48 to get 8.
r=8-8
Subtract 8 from both sides.
r=0
Subtract 8 from 8 to get 0.
r=0 y=-48
The system is now solved.
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