\left. \begin{array} { l } { p = 25000 } \\ { B = 5.85 \% } \end{array} \right.
Solve for p, B
p=25000
B=0.0585
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B=\frac{585}{10000}
Consider the second equation. Expand \frac{5.85}{100} by multiplying both numerator and the denominator by 100.
B=\frac{117}{2000}
Reduce the fraction \frac{585}{10000} to lowest terms by extracting and canceling out 5.
p=25000 B=\frac{117}{2000}
The system is now solved.
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