Solve {l}{n+(-28)=0}{-1=t+(-19)}{14=d+(-10)}{11=-16+y}{5.47=w-(-8)}

$$\left. \begin{array} { l } { n + ( - 28 ) = 0 } \\ { - 1 = t + ( - 19 ) } \\ { 14 = d + ( - 10 ) } \\ { 11 = - 16 + y } \\ { 5.47 = w - ( - 8 ) } \end{array} \right.$$

Solve for n, t, d, y, w

$$y=27$$

$$t=18$$

$$n=28$$

$$d=24$$

$$w=-2.53$$

Solution Steps

Consider the first equation. Add 28 to both sides. Anything plus zero gives itself.

$$n=28$$

Consider the second equation. Swap sides so that all variable terms are on the left hand side.

$$t-19=-1$$

Add 19 to both sides.

$$t=-1+19$$

Add -1 and 19 to get 18.

$$t=18$$

Consider the third equation. Swap sides so that all variable terms are on the left hand side.

$$d-10=14$$

Add 10 to both sides.

$$d=14+10$$

Add 14 and 10 to get 24.

$$d=24$$

Consider the fourth equation. Swap sides so that all variable terms are on the left hand side.

$$-16+y=11$$

Add 16 to both sides.

$$y=11+16$$

Add 11 and 16 to get 27.

$$y=27$$

Consider the fifth equation. The opposite of -8 is 8.

$$5.47=w+8$$

Swap sides so that all variable terms are on the left hand side.

$$w+8=5.47$$

Subtract 8 from both sides.

$$w=5.47-8$$

Subtract 8 from 5.47 to get -2.53.

$$w=-2.53$$

The system is now solved.

$$n=28 t=18 d=24 y=27 w=-2.53$$