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h^{2}\left(h+9\right)-5\left(h+9\right)
Do the grouping h^{3}+9h^{2}-5h-45=\left(h^{3}+9h^{2}\right)+\left(-5h-45\right), and factor out h^{2} in the first and -5 in the second group.
\left(h+9\right)\left(h^{2}-5\right)
Factor out common term h+9 by using distributive property. Polynomial h^{2}-5 is not factored since it does not have any rational roots.