Solve for f, x
x=2
f=0
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f\times 2=2^{3}-2\times 2^{2}
Consider the first equation. Insert the known values of variables into the equation.
f\times 2=8-2\times 2^{2}
Calculate 2 to the power of 3 and get 8.
f\times 2=8-2\times 4
Calculate 2 to the power of 2 and get 4.
f\times 2=8-8
Multiply -2 and 4 to get -8.
f\times 2=0
Subtract 8 from 8 to get 0.
f=0
Divide both sides by 2. Zero divided by any non-zero number gives zero.
f=0 x=2
The system is now solved.
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