Solve for x, y
y=\frac{25f}{3}
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3x=f\times 5
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
y-5x=0
Consider the second equation. Subtract 5x from both sides.
3x=5f,-5x+y=0
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
3x=5f
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
x=\frac{5f}{3}
Divide both sides by 3.
-5\times \frac{5f}{3}+y=0
Substitute \frac{5f}{3} for x in the other equation, -5x+y=0.
-\frac{25f}{3}+y=0
Multiply -5 times \frac{5f}{3}.
y=\frac{25f}{3}
Add \frac{25f}{3} to both sides of the equation.
x=\frac{5f}{3},y=\frac{25f}{3}
The system is now solved.
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