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\frac{1}{2}x+1=f
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}x=f-1
Subtract 1 from both sides.
y-\frac{2}{5}x=-1
Consider the second equation. Subtract \frac{2}{5}x from both sides.
\frac{1}{2}x=f-1,-\frac{2}{5}x+y=-1
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
\frac{1}{2}x=f-1
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
x=2f-2
Multiply both sides by 2.
-\frac{2}{5}\left(2f-2\right)+y=-1
Substitute 2f-2 for x in the other equation, -\frac{2}{5}x+y=-1.
\frac{4-4f}{5}+y=-1
Multiply -\frac{2}{5} times -2+2f.
y=\frac{4f-9}{5}
Subtract \frac{4-4f}{5} from both sides of the equation.
x=2f-2,y=\frac{4f-9}{5}
The system is now solved.