Solve for c, a, b
c=1
a=-\frac{1}{2}=-0.5
b=-1
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4a+2b+1=-3
Substitute 1 for c in the equation 4a+2b+c=-3.
a=-1-\frac{1}{2}b
Solve 4a+2b+1=-3 for a.
b=2\left(-1-\frac{1}{2}b\right)
Substitute -1-\frac{1}{2}b for a in the equation b=2a.
b=-1
Solve b=2\left(-1-\frac{1}{2}b\right) for b.
a=-1-\frac{1}{2}\left(-1\right)
Substitute -1 for b in the equation a=-1-\frac{1}{2}b.
a=-\frac{1}{2}
Calculate a from a=-1-\frac{1}{2}\left(-1\right).
c=1 a=-\frac{1}{2} b=-1
The system is now solved.
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