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a\left(a^{2}+2a-3\right)
Factor out a.
p+q=2 pq=1\left(-3\right)=-3
Consider a^{2}+2a-3. Factor the expression by grouping. First, the expression needs to be rewritten as a^{2}+pa+qa-3. To find p and q, set up a system to be solved.
p=-1 q=3
Since pq is negative, p and q have the opposite signs. Since p+q is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(a^{2}-a\right)+\left(3a-3\right)
Rewrite a^{2}+2a-3 as \left(a^{2}-a\right)+\left(3a-3\right).
a\left(a-1\right)+3\left(a-1\right)
Factor out a in the first and 3 in the second group.
\left(a-1\right)\left(a+3\right)
Factor out common term a-1 by using distributive property.
a\left(a-1\right)\left(a+3\right)
Rewrite the complete factored expression.