Solve {l}{a^2+2bx+c=0(a=0)}{text{then}b^2=}

$$\left. \begin{array} { l } { a ^ { 2 } + 2 b x + c = 0 ( a = 0 ) } \\ { \text { then } b ^ { 2 } = } \end{array} \right.$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{a^{2}+c}{2b}\text{, }&b\neq 0\\x\in \mathrm{C}\text{, }&c=-a^{2}\text{ and }b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract a^{2} from both sides. Anything subtracted from zero gives its negation.

$$2bx+c=-a^{2}$$

Subtract c from both sides.

$$2bx=-a^{2}-c$$

Divide both sides by 2b.

$$\frac{2bx}{2b}=\frac{-a^{2}-c}{2b}$$

Dividing by 2b undoes the multiplication by 2b.

$$x=\frac{-a^{2}-c}{2b}$$

Divide -a^{2}-c by 2b.

$$x=-\frac{a^{2}+c}{2b}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{a^{2}+c}{2b}\text{, }&b\neq 0\\x\in \mathrm{R}\text{, }&c=-a^{2}\text{ and }b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract a^{2} from both sides. Anything subtracted from zero gives its negation.

$$2bx+c=-a^{2}$$

Subtract c from both sides.

$$2bx=-a^{2}-c$$

Divide both sides by 2b.

$$\frac{2bx}{2b}=\frac{-a^{2}-c}{2b}$$

Dividing by 2b undoes the multiplication by 2b.

$$x=\frac{-a^{2}-c}{2b}$$

Divide -a^{2}-c by 2b.

$$x=-\frac{a^{2}+c}{2b}$$