Solve {l}{a=3}{b=4}{c=sqrt{2a+b}}

$$\left. \begin{array} { l } { a = 3 } \\ { b = 4 } \\ { c = \sqrt { 2 a + b } } \end{array} \right.$$

Solve for a, b, c

$$a=3$$

$$b=4$$

$$c=\sqrt{10}\approx 3.16227766$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$c=\sqrt{2\times 3+4}$$

Multiply 2 and 3 to get 6.

$$c=\sqrt{6+4}$$

Add 6 and 4 to get 10.

$$c=\sqrt{10}$$

The system is now solved.

$$a=3 b=4 c=\sqrt{10}$$