Solve for a, b, c
a=1
b=2
c=2
Share
Copied to clipboard
a=-b-c+5
Solve a+b+c=5 for a.
-b-c+5-b-c=-3 -b-c+5+b-c=1
Substitute -b-c+5 for a in the second and third equation.
b=4-c c=2
Solve these equations for b and c respectively.
b=4-2
Substitute 2 for c in the equation b=4-c.
b=2
Calculate b from b=4-2.
a=-2-2+5
Substitute 2 for b and 2 for c in the equation a=-b-c+5.
a=1
Calculate a from a=-2-2+5.
a=1 b=2 c=2
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}