Solve {l}{M+C+H=10}{2M+4C+4H=32}{18m+18c+10H=78}

$$\left. \begin{array} { l } { M + C + H = 10 } \\ { 2 M + 4 C + 4 H = 32 } \\ { 18 m + 18 c + 10 H = 78 } \end{array} \right.$$

Solve for M, C, H, m, c (complex solution)

$$M=4$$

$$C=\frac{9\left(m+c-1\right)}{5}$$

$$H=\frac{3\left(13-3c-3m\right)}{5}$$

$$m\in \mathrm{C}$$

$$c\in \mathrm{C}$$

Solve for M, C, H, m, c

$$M=4$$

$$C=\frac{9\left(m+c-1\right)}{5}$$

$$H=\frac{3\left(13-3c-3m\right)}{5}$$

$$m\in \mathrm{R}$$

$$c\in \mathrm{R}$$