Solve {l}{J=7902*546+5479^2}{H=544*7902+5478^2}

$$\left. \begin{array} { l } { J = 7902 \times 546 + 5479 ^ { 2 } } \\ { H = 544 \times 7902 + 5478 ^ { 2 } } \end{array} \right.$$

Solve for J, H

$$J=34333933$$

$$H=34307172$$

Solution Steps

Consider the first equation. Multiply 7902 and 546 to get 4314492.

$$J=4314492+5479^{2}$$

Calculate 5479 to the power of 2 and get 30019441.

$$J=4314492+30019441$$

Add 4314492 and 30019441 to get 34333933.

$$J=34333933$$

Consider the second equation. Multiply 544 and 7902 to get 4298688.

$$H=4298688+5478^{2}$$

Calculate 5478 to the power of 2 and get 30008484.

$$H=4298688+30008484$$

Add 4298688 and 30008484 to get 34307172.

$$H=34307172$$

The system is now solved.

$$J=34333933 H=34307172$$