Solve {l}{H:x=-2*y=-2}{vec{PH}:x=0quady=1/2}

$$\left. \begin{array} { l } { H : x = - 2 \cdot y = - 2 } \\ { \vec { P H } : x = 0 \quad y = \frac { 1 } { 2 } } \end{array} \right.$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{H}{2y}\text{, }&H\neq 0\text{ and }y\neq 0\\x\neq 0\text{, }&y=0\text{ and }H=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$H=-2yx$$

Swap sides so that all variable terms are on the left hand side.

$$-2yx=H$$

The equation is in standard form.

$$\left(-2y\right)x=H$$

Divide both sides by -2y.

$$\frac{\left(-2y\right)x}{-2y}=\frac{H}{-2y}$$

Dividing by -2y undoes the multiplication by -2y.

$$x=\frac{H}{-2y}$$

Divide H by -2y.

$$x=-\frac{H}{2y}$$

Variable x cannot be equal to 0.

$$x=-\frac{H}{2y}\text{, }x\neq 0$$