Solve {l}{D=A+206}{100+6A=9888}

$$\left. \begin{array} { l } { D = A + 206 } \\ { 100 + 6 A = 9888 } \end{array} \right.$$

Solve for D, A

$$D = \frac{5512}{3} = 1837\frac{1}{3} \approx 1837.333333333$$

$$A = \frac{4894}{3} = 1631\frac{1}{3} \approx 1631.333333333$$

Solution Steps

Consider the second equation. Subtract 100 from both sides.

$$6A=9888-100$$

Subtract 100 from 9888 to get 9788.

$$6A=9788$$

Divide both sides by 6.

$$A=\frac{9788}{6}$$

Reduce the fraction \frac{9788}{6} to lowest terms by extracting and canceling out 2.

$$A=\frac{4894}{3}$$

Consider the first equation. Insert the known values of variables into the equation.

$$D=\frac{4894}{3}+206$$

Add \frac{4894}{3} and 206 to get \frac{5512}{3}.

$$D=\frac{5512}{3}$$

The system is now solved.

$$D=\frac{5512}{3} A=\frac{4894}{3}$$