Solve {l}{B=-(-3)*(+4)-(-7+8)}{Gamma=7*(-8)-[-(8-9)+12]}

$$\left. \begin{array} { l } { B = - ( - 3 ) \cdot ( + 4 ) - ( - 7 + 8 ) } \\ { \Gamma = 7 \cdot ( - 8 ) - [ - ( 8 - 9 ) + 12 ] } \end{array} \right.$$

Solve for B, Γ

$$B=11$$

$$\Gamma =-69$$

Solution Steps

Consider the first equation. The opposite of -3 is 3.

$$B=3\times 4-\left(-7+8\right)$$

Multiply 3 and 4 to get 12.

$$B=12-\left(-7+8\right)$$

Add -7 and 8 to get 1.

$$B=12-1$$

Subtract 1 from 12 to get 11.

$$B=11$$

Consider the second equation. Multiply 7 and -8 to get -56.

$$\Gamma =-56-\left(-\left(8-9\right)+12\right)$$

Subtract 9 from 8 to get -1.

$$\Gamma =-56-\left(-\left(-1\right)+12\right)$$

The opposite of -1 is 1.

$$\Gamma =-56-\left(1+12\right)$$

Add 1 and 12 to get 13.

$$\Gamma =-56-13$$

Subtract 13 from -56 to get -69.

$$\Gamma =-69$$

The system is now solved.

$$B=11 \Gamma =-69$$