Solve for A, P
A=1815
P=1650
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A=1650\left(1+\frac{10}{100}\right)
Consider the first equation. Insert the known values of variables into the equation.
A=1650\left(1+\frac{1}{10}\right)
Reduce the fraction \frac{10}{100} to lowest terms by extracting and canceling out 10.
A=1650\times \frac{11}{10}
Add 1 and \frac{1}{10} to get \frac{11}{10}.
A=1815
Multiply 1650 and \frac{11}{10} to get 1815.
A=1815 P=1650
The system is now solved.
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