Solve {l}{A=180^circ}{B=2335A}{x=A/A+B}

$$\left. \begin{array} { l } { A = 180 ^ { \circ } } \\ { B = 2335 A } \\ { x = \frac { A } { A + B } } \end{array} \right.$$

Solve for A, B, x

$$x=\frac{1}{2336}\approx 0.000428082$$

$$A=180$$

$$B=420300$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$B=2335\times 180$$

Multiply 2335 and 180 to get 420300.

$$B=420300$$

Consider the third equation. Insert the known values of variables into the equation.

$$x=\frac{180}{180+420300}$$

Add 180 and 420300 to get 420480.

$$x=\frac{180}{420480}$$

Reduce the fraction \frac{180}{420480} to lowest terms by extracting and canceling out 180.

$$x=\frac{1}{2336}$$

The system is now solved.

$$A=180 B=420300 x=\frac{1}{2336}$$