Solve {l}{A=(3-5)^2}{B=(9-7)^3}{C=(-1/2+1/3)^2}

$$\left. \begin{array} { l } { A = ( 3 - 5 ) ^ { 2 } } \\ { B = ( 9 - 7 ) ^ { 3 } } \\ { C = ( - \frac { 1 } { 2 } + \frac { 1 } { 3 } ) ^ { 2 } } \end{array} \right.$$

Solve for A, B, C

$$A=4$$

$$B=8$$

$$C=\frac{1}{36}\approx 0.027777778$$

Solution Steps

Consider the first equation. Subtract 5 from 3 to get -2.

$$A=\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$A=4$$

Consider the second equation. Subtract 7 from 9 to get 2.

$$B=2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$B=8$$

Consider the third equation. Add -\frac{1}{2} and \frac{1}{3} to get -\frac{1}{6}.

$$C=\left(-\frac{1}{6}\right)^{2}$$

Calculate -\frac{1}{6} to the power of 2 and get \frac{1}{36}.

$$C=\frac{1}{36}$$

The system is now solved.

$$A=4 B=8 C=\frac{1}{36}$$