Solve {l}{A=h(a+b)/2}{a=8.4}{h=6.3}{b=13.6}

$$\left. \begin{array} { l } { A = \frac { h ( a + b ) } { 2 } } \\ { a = 8.4 } \\ { h = 6.3 } \\ { b = 13.6 } \end{array} \right.$$

Solve for A, h, a, b

$$A=69.3$$

$$h=6.3$$

$$a=8.4$$

$$b=13.6$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$A=\frac{6.3\left(8.4+13.6\right)}{2}$$

Add 8.4 and 13.6 to get 22.

$$A=\frac{6.3\times 22}{2}$$

Multiply 6.3 and 22 to get 138.6.

$$A=\frac{138.6}{2}$$

Expand \frac{138.6}{2} by multiplying both numerator and the denominator by 10.

$$A=\frac{1386}{20}$$

Reduce the fraction \frac{1386}{20} to lowest terms by extracting and canceling out 2.

$$A=\frac{693}{10}$$

The system is now solved.

$$A=\frac{693}{10} h=6.3 a=8.4 b=13.6$$