Solve {l}{A:y=2x+5text{where}-3leqxleq-2}{text{B:}y=1text{where}-2leqxleq2}{text{C:}y=2x-3text{where}1leqxleq2}{text{D:}y=-1text{where}-3leqxleq1}

$$\left. \begin{array} { l } { A : y = 2 x + 5 \text { where } - 3 \leq x \leq - 2 } \\ { \text { B: } y = 1 \text { where } - 2 \leq x \leq 2 } \\ { \text { C: } y = 2 x - 3 \text { where } 1 \leq x \leq 2 } \\ { \text { D: } y = - 1 \text { where } - 3 \leq x \leq 1 } \end{array} \right.$$

Solve for A, y, x

$$x=2$$

$$y=1$$

$$A=9$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$1=2x-3$$

Swap sides so that all variable terms are on the left hand side.

$$2x-3=1$$

Add 3 to both sides.

$$2x=1+3$$

Add 1 and 3 to get 4.

$$2x=4$$

Divide both sides by 2.

$$x=\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$x=2$$

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{A}{1}=2\times 2+5$$

Anything divided by one gives itself.

$$A=2\times 2+5$$

Multiply 2 and 2 to get 4.

$$A=4+5$$

Add 4 and 5 to get 9.

$$A=9$$

The system is now solved.

$$A=9 y=1 x=2$$