Solve {l}{92-2a+b=82}{238-4a=206}

$$\left. \begin{array} { l } { 92 - 2 a + b = 82 } \\ { 238 - 4 a = 206 } \end{array} \right.$$

Solve for a, b

$$a=8$$

$$b=6$$

Solution Steps

Consider the second equation. Subtract 238 from both sides.

$$-4a=206-238$$

Subtract 238 from 206 to get -32.

$$-4a=-32$$

Divide both sides by -4.

$$a=\frac{-32}{-4}$$

Divide -32 by -4 to get 8.

$$a=8$$

Consider the first equation. Insert the known values of variables into the equation.

$$92-2\times 8+b=82$$

Multiply -2 and 8 to get -16.

$$92-16+b=82$$

Subtract 16 from 92 to get 76.

$$76+b=82$$

Subtract 76 from both sides.

$$b=82-76$$

Subtract 76 from 82 to get 6.

$$b=6$$

The system is now solved.

$$a=8 b=6$$