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Solve for x, y
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9x+0=8
Consider the first equation. Anything times zero gives zero.
9x=8
Anything plus zero gives itself.
x=\frac{8}{9}
Divide both sides by 9.
0\times \frac{8}{9}+3y=-2
Consider the second equation. Insert the known values of variables into the equation.
0+3y=-2
Multiply 0 and \frac{8}{9} to get 0.
3y=-2
Anything plus zero gives itself.
y=-\frac{2}{3}
Divide both sides by 3.
x=\frac{8}{9} y=-\frac{2}{3}
The system is now solved.