Solve {l}{9-3/5+62/3(226/15)}{20(226)-42}

$$\left. \begin{array} { l } { 9 - \frac { 3 } { 5 } + 6 \frac { 2 } { 3 } ( \frac { 226 } { 15 } ) } \\ { 20 ( 226 ) - 42 } \end{array} \right.$$

Sort

$$\frac{4898}{45},\ 4478$$

Solution Steps

Convert 9 to fraction \frac{45}{5}.

$$sort(\frac{45}{5}-\frac{3}{5}+\frac{6\times 3+2}{3}\times \frac{226}{15},20\times 226-42)$$

Since \frac{45}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{45-3}{5}+\frac{6\times 3+2}{3}\times \frac{226}{15},20\times 226-42)$$

Subtract 3 from 45 to get 42.

$$sort(\frac{42}{5}+\frac{6\times 3+2}{3}\times \frac{226}{15},20\times 226-42)$$

Multiply 6 and 3 to get 18.

$$sort(\frac{42}{5}+\frac{18+2}{3}\times \frac{226}{15},20\times 226-42)$$

Add 18 and 2 to get 20.

$$sort(\frac{42}{5}+\frac{20}{3}\times \frac{226}{15},20\times 226-42)$$

Multiply \frac{20}{3} times \frac{226}{15} by multiplying numerator times numerator and denominator times denominator.

$$sort(\frac{42}{5}+\frac{20\times 226}{3\times 15},20\times 226-42)$$

Do the multiplications in the fraction \frac{20\times 226}{3\times 15}.

$$sort(\frac{42}{5}+\frac{4520}{45},20\times 226-42)$$

Reduce the fraction \frac{4520}{45} to lowest terms by extracting and canceling out 5.

$$sort(\frac{42}{5}+\frac{904}{9},20\times 226-42)$$

Least common multiple of 5 and 9 is 45. Convert \frac{42}{5} and \frac{904}{9} to fractions with denominator 45.

$$sort(\frac{378}{45}+\frac{4520}{45},20\times 226-42)$$

Since \frac{378}{45} and \frac{4520}{45} have the same denominator, add them by adding their numerators.

$$sort(\frac{378+4520}{45},20\times 226-42)$$

Add 378 and 4520 to get 4898.

$$sort(\frac{4898}{45},20\times 226-42)$$

Multiply 20 and 226 to get 4520.

$$sort(\frac{4898}{45},4520-42)$$

Subtract 42 from 4520 to get 4478.

$$sort(\frac{4898}{45},4478)$$

Convert decimal numbers in the list \frac{4898}{45},4478 to fractions.

$$\frac{4898}{45},4478$$

Evaluate

$$\frac{4898}{45},\ 4478$$