Solve for n, b, a
n=-\frac{\sqrt{3}-729}{3b^{7}}\text{, }b\in \mathrm{R}\setminus -1,0\text{, }a=\frac{3^{\frac{6}{7}}\sqrt[7]{\frac{b^{3}+1}{b}}}{3}
n=\frac{\sqrt{3}-729}{3}\approx -242.422649731\text{, }b=-1\text{, }a=0
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