Solve for z, a
a=19
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z=\frac{100}{6}
Consider the first equation. Divide both sides by 6.
z=\frac{50}{3}
Reduce the fraction \frac{100}{6} to lowest terms by extracting and canceling out 2.
a=13+6
Consider the second equation. Add 9 and 4 to get 13.
a=19
Add 13 and 6 to get 19.
z=\frac{50}{3} a=19
The system is now solved.
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