Solve {l}{830/245}{24/32}{32/30}

$$\left. \begin{array} { l } { 8 \frac { 30 } { 245 } } \\ { \frac { 24 } { 32 } } \\ { \frac { 32 } { 30 } } \end{array} \right.$$

Sort

$$\frac{3}{4},\frac{16}{15},\frac{398}{49}$$

Solution Steps

Multiply 8 and 245 to get 1960.

$$sort(\frac{1960+30}{245},\frac{24}{32},\frac{32}{30})$$

Add 1960 and 30 to get 1990.

$$sort(\frac{1990}{245},\frac{24}{32},\frac{32}{30})$$

Reduce the fraction \frac{1990}{245} to lowest terms by extracting and canceling out 5.

$$sort(\frac{398}{49},\frac{24}{32},\frac{32}{30})$$

Reduce the fraction \frac{24}{32} to lowest terms by extracting and canceling out 8.

$$sort(\frac{398}{49},\frac{3}{4},\frac{32}{30})$$

Reduce the fraction \frac{32}{30} to lowest terms by extracting and canceling out 2.

$$sort(\frac{398}{49},\frac{3}{4},\frac{16}{15})$$

Least common denominator of the numbers in the list \frac{398}{49},\frac{3}{4},\frac{16}{15} is 2940. Convert numbers in the list to fractions with denominator 2940.

$$\frac{23880}{2940},\frac{2205}{2940},\frac{3136}{2940}$$

To sort the list, start from a single element \frac{23880}{2940}.

$$\frac{23880}{2940}$$

Insert \frac{2205}{2940} to the appropriate location in the new list.

$$\frac{2205}{2940},\frac{23880}{2940}$$

Insert \frac{3136}{2940} to the appropriate location in the new list.

$$\frac{2205}{2940},\frac{3136}{2940},\frac{23880}{2940}$$

Replace the obtained fractions with the initial values.

$$\frac{3}{4},\frac{16}{15},\frac{398}{49}$$

Evaluate

$$\frac{398}{49},\ \frac{3}{4},\ \frac{16}{15}$$