Solve {l}{8+x=0}{72+8y+5x=0}

$$\left. \begin{array} { l } { 8 + x = 0 } \\ { 72 + 8 y + 5 x = 0 } \end{array} \right.$$

Solve for x, y

$$x=-8$$

$$y=-4$$

Solution Steps

Consider the first equation. Subtract 8 from both sides. Anything subtracted from zero gives its negation.

$$x=-8$$

Consider the second equation. Insert the known values of variables into the equation.

$$72+8y+5\left(-8\right)=0$$

Multiply 5 and -8 to get -40.

$$72+8y-40=0$$

Subtract 40 from 72 to get 32.

$$32+8y=0$$

Subtract 32 from both sides. Anything subtracted from zero gives its negation.

$$8y=-32$$

Divide both sides by 8.

$$y=\frac{-32}{8}$$

Divide -32 by 8 to get -4.

$$y=-4$$

The system is now solved.

$$x=-8 y=-4$$