Solve {l}{75-12*3div8}{7*6+3-(4+6)}{10*6+3+45}{(13-4)*(63+9)}

$$\left. \begin{array} { l } { 75 - 12 \times 3 \div 8 } \\ { 7 \times 6 + 3 - ( 4 + 6 ) } \\ { 10 \times 6 + 3 + 45 } \\ { ( 13 - 4 ) \times ( 63 + 9 ) } \end{array} \right.$$

Sort

$$35,\frac{141}{2},108,648$$

Solution Steps

Multiply 12 and 3 to get 36.

$$sort(75-\frac{36}{8},7\times 6+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Reduce the fraction \frac{36}{8} to lowest terms by extracting and canceling out 4.

$$sort(75-\frac{9}{2},7\times 6+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Convert 75 to fraction \frac{150}{2}.

$$sort(\frac{150}{2}-\frac{9}{2},7\times 6+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Since \frac{150}{2} and \frac{9}{2} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{150-9}{2},7\times 6+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Subtract 9 from 150 to get 141.

$$sort(\frac{141}{2},7\times 6+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Multiply 7 and 6 to get 42.

$$sort(\frac{141}{2},42+3-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Add 42 and 3 to get 45.

$$sort(\frac{141}{2},45-\left(4+6\right),10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Add 4 and 6 to get 10.

$$sort(\frac{141}{2},45-10,10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Subtract 10 from 45 to get 35.

$$sort(\frac{141}{2},35,10\times 6+3+45,\left(13-4\right)\left(63+9\right))$$

Multiply 10 and 6 to get 60.

$$sort(\frac{141}{2},35,60+3+45,\left(13-4\right)\left(63+9\right))$$

Add 60 and 3 to get 63.

$$sort(\frac{141}{2},35,63+45,\left(13-4\right)\left(63+9\right))$$

Add 63 and 45 to get 108.

$$sort(\frac{141}{2},35,108,\left(13-4\right)\left(63+9\right))$$

Subtract 4 from 13 to get 9.

$$sort(\frac{141}{2},35,108,9\left(63+9\right))$$

Add 63 and 9 to get 72.

$$sort(\frac{141}{2},35,108,9\times 72)$$

Multiply 9 and 72 to get 648.

$$sort(\frac{141}{2},35,108,648)$$

Convert decimal numbers in the list \frac{141}{2},35,108,648 to fractions.

$$\frac{141}{2},35,108,648$$

To sort the list, start from a single element \frac{141}{2}.

$$\frac{141}{2}$$

Insert 35 to the appropriate location in the new list.

$$35,\frac{141}{2}$$

Insert 108 to the appropriate location in the new list.

$$35,\frac{141}{2},108$$

Insert 648 to the appropriate location in the new list.

$$35,\frac{141}{2},108,648$$

Evaluate

$$\frac{141}{2},\ 35,\ 108,\ 648$$