Solve {l}{7x=2[(1+i)^3-1](1+}{i)^3}

$$\left. \begin{array} { l } { 7 x = 2 [ ( 1 + i ) ^ { 3 } - 1 ] ( 1 + } \\ { i ) ^ { 3 } } \end{array} \right.$$

Solve for x

$$x=-\frac{6}{7}+\frac{4}{7}i\approx -0.857142857+0.571428571i$$

Steps for Solving Linear Equation

Calculate 1+i to the power of 3 and get -2+2i.

$$7x=2\left(-2+2i-1\right)$$

Subtract 1 from -2+2i to get -3+2i.

$$7x=2\left(-3+2i\right)$$

Multiply 2 and -3+2i to get -6+4i.

$$7x=-6+4i$$

Divide both sides by 7.

$$x=\frac{-6+4i}{7}$$

Divide -6+4i by 7 to get -\frac{6}{7}+\frac{4}{7}i.

$$x=-\frac{6}{7}+\frac{4}{7}i$$