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7x=35-4
Consider the first equation. Subtract 4 from both sides.
7x=31
Subtract 4 from 35 to get 31.
x=\frac{31}{7}
Divide both sides by 7.
4y+2\times \frac{31}{7}=200
Consider the second equation. Insert the known values of variables into the equation.
4y+\frac{62}{7}=200
Multiply 2 and \frac{31}{7} to get \frac{62}{7}.
4y=200-\frac{62}{7}
Subtract \frac{62}{7} from both sides.
4y=\frac{1338}{7}
Subtract \frac{62}{7} from 200 to get \frac{1338}{7}.
y=\frac{\frac{1338}{7}}{4}
Divide both sides by 4.
y=\frac{1338}{7\times 4}
Express \frac{\frac{1338}{7}}{4} as a single fraction.
y=\frac{1338}{28}
Multiply 7 and 4 to get 28.
y=\frac{669}{14}
Reduce the fraction \frac{1338}{28} to lowest terms by extracting and canceling out 2.
x=\frac{31}{7} y=\frac{669}{14}
The system is now solved.