Solve {l}{7^{2}-3^{2}+6^{2}:2-3^{2}*2}{2^{5}-2^{2}*3+3^{3}+2-7^{2}}{3^{3}-(3^2-2^3)*5^2+4^2:2}

$$\left. \begin{array} { l } { 7 ^ { 2 } - 3 ^ { 2 } + 6 ^ { 2 } : 2 - 3 ^ { 2 } \times 2 } \\ { 2 ^ { 5 } - 2 ^ { 2 } \times 3 + 3 ^ { 3 } + 2 - 7 ^ { 2 } } \\ { 3 ^ { 3 } - ( 3 ^ { 2 } - 2 ^ { 3 } ) \times 5 ^ { 2 } + 4 ^ { 2 } : 2 } \end{array} \right.$$

Sort

$$0,10,40$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$sort(49-3^{2}+\frac{6^{2}}{2}-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 3 to the power of 2 and get 9.

$$sort(49-9+\frac{6^{2}}{2}-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Subtract 9 from 49 to get 40.

$$sort(40+\frac{6^{2}}{2}-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 6 to the power of 2 and get 36.

$$sort(40+\frac{36}{2}-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Divide 36 by 2 to get 18.

$$sort(40+18-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Add 40 and 18 to get 58.

$$sort(58-3^{2}\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 3 to the power of 2 and get 9.

$$sort(58-9\times 2,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Multiply 9 and 2 to get 18.

$$sort(58-18,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Subtract 18 from 58 to get 40.

$$sort(40,2^{5}-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 2 to the power of 5 and get 32.

$$sort(40,32-2^{2}\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 2 to the power of 2 and get 4.

$$sort(40,32-4\times 3+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Multiply 4 and 3 to get 12.

$$sort(40,32-12+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Subtract 12 from 32 to get 20.

$$sort(40,20+3^{3}+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 3 to the power of 3 and get 27.

$$sort(40,20+27+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Add 20 and 27 to get 47.

$$sort(40,47+2-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Add 47 and 2 to get 49.

$$sort(40,49-7^{2},3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 7 to the power of 2 and get 49.

$$sort(40,49-49,3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Subtract 49 from 49 to get 0.

$$sort(40,0,3^{3}-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 3 to the power of 3 and get 27.

$$sort(40,0,27-\left(3^{2}-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 3 to the power of 2 and get 9.

$$sort(40,0,27-\left(9-2^{3}\right)\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 2 to the power of 3 and get 8.

$$sort(40,0,27-\left(9-8\right)\times 5^{2}+\frac{4^{2}}{2})$$

Subtract 8 from 9 to get 1.

$$sort(40,0,27-1\times 5^{2}+\frac{4^{2}}{2})$$

Calculate 5 to the power of 2 and get 25.

$$sort(40,0,27-1\times 25+\frac{4^{2}}{2})$$

Multiply 1 and 25 to get 25.

$$sort(40,0,27-25+\frac{4^{2}}{2})$$

Subtract 25 from 27 to get 2.

$$sort(40,0,2+\frac{4^{2}}{2})$$

Calculate 4 to the power of 2 and get 16.

$$sort(40,0,2+\frac{16}{2})$$

Divide 16 by 2 to get 8.

$$sort(40,0,2+8)$$

Add 2 and 8 to get 10.

$$sort(40,0,10)$$

To sort the list, start from a single element 40.

$$40$$

Insert 0 to the appropriate location in the new list.

$$0,40$$

Insert 10 to the appropriate location in the new list.

$$0,10,40$$

Evaluate

$$40,\ 0,\ 10$$