Solve for y, z
y=\frac{2}{3}\approx 0.666666667
z = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
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z=\frac{4}{3}
Consider the second equation. Divide both sides by 3.
6y=3\times \frac{4}{3}
Consider the first equation. Insert the known values of variables into the equation.
6y=4
Multiply 3 and \frac{4}{3} to get 4.
y=\frac{4}{6}
Divide both sides by 6.
y=\frac{2}{3}
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
y=\frac{2}{3} z=\frac{4}{3}
The system is now solved.
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