Solve for x, y
x=35-\frac{201}{400t}
y=\frac{201}{t}
t\neq 0
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ty=201,0.015y+6x=210
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
ty=201
Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.
y=\frac{201}{t}
Divide both sides by t.
0.015\times \frac{201}{t}+6x=210
Substitute \frac{201}{t} for y in the other equation, 0.015y+6x=210.
\frac{603}{200t}+6x=210
Multiply 0.015 times \frac{201}{t}.
6x=210-\frac{603}{200t}
Subtract \frac{603}{200t} from both sides of the equation.
x=35-\frac{201}{400t}
Divide both sides by 6.
y=\frac{201}{t},x=35-\frac{201}{400t}
The system is now solved.
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