Solve {l}{6*0-3geq0+7}{7(0)+3leq15+3(-0)}

$$\left. \begin{array} { l } { 6 \times 0 - 3 \geq 0 + 7 } \\ { 7 ( 0 ) + 3 \leq 15 + 3 ( - 0 ) } \end{array} \right.$$

Verify

Solution Steps

Multiply 6 and 0 to get 0.

$$0-3\geq 0+7\text{ and }7\times 0+3\leq 15+3\times 0$$

Subtract 3 from 0 to get -3.

$$-3\geq 0+7\text{ and }7\times 0+3\leq 15+3\times 0$$

Add 0 and 7 to get 7.

$$-3\geq 7\text{ and }7\times 0+3\leq 15+3\times 0$$

Compare -3 and 7.

$$\text{false}\text{ and }7\times 0+3\leq 15+3\times 0$$

Multiply 7 and 0 to get 0.

$$\text{false}\text{ and }0+3\leq 15+3\times 0$$

Add 0 and 3 to get 3.

$$\text{false}\text{ and }3\leq 15+3\times 0$$

Multiply 3 and 0 to get 0.

$$\text{false}\text{ and }3\leq 15+0$$

Add 15 and 0 to get 15.

$$\text{false}\text{ and }3\leq 15$$

Compare 3 and 15.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$