Solve {l}{61/8-43/8}{4^3-5^1+3}

$$\left. \begin{array} { l } { 6 \frac { 1 } { 8 } - 4 \frac { 3 } { 8 } } \\ { 4 ^ { 3 } - 5 ^ { 1 } + 3 } \end{array} \right.$$

Sort

$$\frac{7}{4},\ 62$$

Solution Steps

Multiply 6 and 8 to get 48.

$$sort(\frac{48+1}{8}-\frac{4\times 8+3}{8},4^{3}-5^{1}+3)$$

Add 48 and 1 to get 49.

$$sort(\frac{49}{8}-\frac{4\times 8+3}{8},4^{3}-5^{1}+3)$$

Multiply 4 and 8 to get 32.

$$sort(\frac{49}{8}-\frac{32+3}{8},4^{3}-5^{1}+3)$$

Add 32 and 3 to get 35.

$$sort(\frac{49}{8}-\frac{35}{8},4^{3}-5^{1}+3)$$

Since \frac{49}{8} and \frac{35}{8} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{49-35}{8},4^{3}-5^{1}+3)$$

Subtract 35 from 49 to get 14.

$$sort(\frac{14}{8},4^{3}-5^{1}+3)$$

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$sort(\frac{7}{4},4^{3}-5^{1}+3)$$

Calculate 4 to the power of 3 and get 64.

$$sort(\frac{7}{4},64-5^{1}+3)$$

Calculate 5 to the power of 1 and get 5.

$$sort(\frac{7}{4},64-5+3)$$

Subtract 5 from 64 to get 59.

$$sort(\frac{7}{4},59+3)$$

Add 59 and 3 to get 62.

$$sort(\frac{7}{4},62)$$

Convert decimal numbers in the list \frac{7}{4},62 to fractions.

$$\frac{7}{4},62$$

Evaluate

$$\frac{7}{4},\ 62$$