Solve {l}{6^2+4^2=0}{6^2+8^2=0}

$$\left. \begin{array} { l } { 6 ^ { 2 } + 4 ^ { 2 } = 0 } \\ { 6 ^ { 2 } + 8 ^ { 2 } = 0 } \end{array} \right.$$

Verify

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$36+4^{2}=0\text{ and }6^{2}+8^{2}=0$$

Calculate 4 to the power of 2 and get 16.

$$36+16=0\text{ and }6^{2}+8^{2}=0$$

Add 36 and 16 to get 52.

$$52=0\text{ and }6^{2}+8^{2}=0$$

Compare 52 and 0.

$$\text{false}\text{ and }6^{2}+8^{2}=0$$

Calculate 6 to the power of 2 and get 36.

$$\text{false}\text{ and }36+8^{2}=0$$

Calculate 8 to the power of 2 and get 64.

$$\text{false}\text{ and }36+64=0$$

Add 36 and 64 to get 100.

$$\text{false}\text{ and }100=0$$

Compare 100 and 0.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$