Solve {l}{6=b}{0=4a+b}

$$\left. \begin{array} { l } { 6 = b } \\ { 0 = 4 a + b } \end{array} \right.$$

Solve for b, a

$$b=6$$

$$a = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$b=6$$

Consider the second equation. Insert the known values of variables into the equation.

$$0=4a+6$$

Swap sides so that all variable terms are on the left hand side.

$$4a+6=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$4a=-6$$

Divide both sides by 4.

$$a=\frac{-6}{4}$$

Reduce the fraction \frac{-6}{4} to lowest terms by extracting and canceling out 2.

$$a=-\frac{3}{2}$$

The system is now solved.

$$b=6 a=-\frac{3}{2}$$