Solve {l}{52+33:3}{28:7+(6*7+3^3):2}

$$\left. \begin{array} { l } { 52 + 33 : 3 } \\ { 28 : 7 + ( 6 \cdot 7 + 3 ^ { 3 } ) : 2 } \end{array} \right.$$

Sort

$$\frac{77}{2},63$$

Solution Steps

Divide 33 by 3 to get 11.

$$sort(52+11,\frac{28}{7}+\frac{6\times 7+3^{3}}{2})$$

Add 52 and 11 to get 63.

$$sort(63,\frac{28}{7}+\frac{6\times 7+3^{3}}{2})$$

Divide 28 by 7 to get 4.

$$sort(63,4+\frac{6\times 7+3^{3}}{2})$$

Multiply 6 and 7 to get 42.

$$sort(63,4+\frac{42+3^{3}}{2})$$

Calculate 3 to the power of 3 and get 27.

$$sort(63,4+\frac{42+27}{2})$$

Add 42 and 27 to get 69.

$$sort(63,4+\frac{69}{2})$$

Convert 4 to fraction \frac{8}{2}.

$$sort(63,\frac{8}{2}+\frac{69}{2})$$

Since \frac{8}{2} and \frac{69}{2} have the same denominator, add them by adding their numerators.

$$sort(63,\frac{8+69}{2})$$

Add 8 and 69 to get 77.

$$sort(63,\frac{77}{2})$$

Convert decimal numbers in the list 63,\frac{77}{2} to fractions.

$$63,\frac{77}{2}$$

To sort the list, start from a single element 63.

$$63$$

Insert \frac{77}{2} to the appropriate location in the new list.

$$\frac{77}{2},63$$

Evaluate

$$63,\ \frac{77}{2}$$