Solve for x, y
x=25c-\frac{21}{2}
y=\frac{41-50c}{3}
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3y+50c=41,3y+2x=20
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
3y+50c=41
Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.
3y=41-50c
Subtract 50c from both sides of the equation.
y=\frac{41-50c}{3}
Divide both sides by 3.
3\times \frac{41-50c}{3}+2x=20
Substitute \frac{41-50c}{3} for y in the other equation, 3y+2x=20.
41-50c+2x=20
Multiply 3 times \frac{41-50c}{3}.
2x=50c-21
Subtract 41-50c from both sides of the equation.
x=25c-\frac{21}{2}
Divide both sides by 2.
y=\frac{41-50c}{3},x=25c-\frac{21}{2}
The system is now solved.
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