Solve {l}{5x+-4=50}{9x+14y=97}

$$\left. \begin{array} { l } { 5 x + - 4 = 50 } \\ { 9 x + 14 y = 97 } \end{array} \right.$$

Solve for x, y

$$x = \frac{54}{5} = 10\frac{4}{5} = 10.8$$

$$y=-\frac{1}{70}\approx -0.014285714$$

Solution Steps

Consider the first equation. Add 4 to both sides.

$$5x=50+4$$

Add 50 and 4 to get 54.

$$5x=54$$

Divide both sides by 5.

$$x=\frac{54}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$9\times \frac{54}{5}+14y=97$$

Multiply 9 and \frac{54}{5} to get \frac{486}{5}.

$$\frac{486}{5}+14y=97$$

Subtract \frac{486}{5} from both sides.

$$14y=97-\frac{486}{5}$$

Subtract \frac{486}{5} from 97 to get -\frac{1}{5}.

$$14y=-\frac{1}{5}$$

Divide both sides by 14.

$$y=\frac{-\frac{1}{5}}{14}$$

Express \frac{-\frac{1}{5}}{14} as a single fraction.

$$y=\frac{-1}{5\times 14}$$

Multiply 5 and 14 to get 70.

$$y=\frac{-1}{70}$$

Fraction \frac{-1}{70} can be rewritten as -\frac{1}{70} by extracting the negative sign.

$$y=-\frac{1}{70}$$

The system is now solved.

$$x=\frac{54}{5} y=-\frac{1}{70}$$