Solve {l}{5-[63-2-(12-8)-3+6]}{18div[12div(-2)]}

$$\left. \begin{array} { l } { 5 - [ 63 - 2 - ( 12 - 8 ) - 3 + 6 ] } \\ { 18 \div [ 12 \div ( - 2 ) ] } \end{array} \right.$$

Sort

$$-55,\ -3$$

Solution Steps

Subtract 2 from 63 to get 61.

$$sort(5-\left(61-\left(12-8\right)-3+6\right),\frac{18}{\frac{12}{-2}})$$

Subtract 8 from 12 to get 4.

$$sort(5-\left(61-4-3+6\right),\frac{18}{\frac{12}{-2}})$$

Subtract 4 from 61 to get 57.

$$sort(5-\left(57-3+6\right),\frac{18}{\frac{12}{-2}})$$

Subtract 3 from 57 to get 54.

$$sort(5-\left(54+6\right),\frac{18}{\frac{12}{-2}})$$

Add 54 and 6 to get 60.

$$sort(5-60,\frac{18}{\frac{12}{-2}})$$

Subtract 60 from 5 to get -55.

$$sort(-55,\frac{18}{\frac{12}{-2}})$$

Divide 18 by \frac{12}{-2} by multiplying 18 by the reciprocal of \frac{12}{-2}.

$$sort(-55,\frac{18\left(-2\right)}{12})$$

Multiply 18 and -2 to get -36.

$$sort(-55,\frac{-36}{12})$$

Divide -36 by 12 to get -3.

$$sort(-55,-3)$$

The list values are already in order.

$$-55,-3$$

Evaluate

$$-55,\ -3$$