Solve {l}{5-[6-3-(1-8)-3+6]+5}{9div[6div(-4+2)]}

$$\left. \begin{array} { l } { 5 - [ 6 - 3 - ( 1 - 8 ) - 3 + 6 ] + 5 } \\ { 9 \div [ 6 \div ( - 4 + 2 ) ] } \end{array} \right.$$

Sort

$$-3,\ -3$$

Solution Steps

Subtract 3 from 6 to get 3.

$$sort(5-\left(3-\left(1-8\right)-3+6\right)+5,\frac{9}{\frac{6}{-4+2}})$$

Subtract 8 from 1 to get -7.

$$sort(5-\left(3-\left(-7\right)-3+6\right)+5,\frac{9}{\frac{6}{-4+2}})$$

The opposite of -7 is 7.

$$sort(5-\left(3+7-3+6\right)+5,\frac{9}{\frac{6}{-4+2}})$$

Add 3 and 7 to get 10.

$$sort(5-\left(10-3+6\right)+5,\frac{9}{\frac{6}{-4+2}})$$

Subtract 3 from 10 to get 7.

$$sort(5-\left(7+6\right)+5,\frac{9}{\frac{6}{-4+2}})$$

Add 7 and 6 to get 13.

$$sort(5-13+5,\frac{9}{\frac{6}{-4+2}})$$

Subtract 13 from 5 to get -8.

$$sort(-8+5,\frac{9}{\frac{6}{-4+2}})$$

Add -8 and 5 to get -3.

$$sort(-3,\frac{9}{\frac{6}{-4+2}})$$

Divide 9 by \frac{6}{-4+2} by multiplying 9 by the reciprocal of \frac{6}{-4+2}.

$$sort(-3,\frac{9\left(-4+2\right)}{6})$$

Add -4 and 2 to get -2.

$$sort(-3,\frac{9\left(-2\right)}{6})$$

Multiply 9 and -2 to get -18.

$$sort(-3,\frac{-18}{6})$$

Divide -18 by 6 to get -3.

$$sort(-3,-3)$$

The list values are already in order.

$$-3,-3$$

Evaluate

$$-3,\ -3$$