Solve {l}{5^{0}+(0,25)^{-2}-(0,5)^{-2}-2^4}{(2^-1-1)^-1+(-2)^3}

$$\left. \begin{array} { l } { 5 ^ { 0 } + ( 0,25 ) ^ { - 2 } - ( 0,5 ) ^ { - 2 } - 2 ^ { 4 } } \\ { ( 2 ^ { - 1 } - 1 ) ^ { - 1 } + ( - 2 ) ^ { 3 } } \end{array} \right.$$

Sort

$$-10;-3$$

Solution Steps

Calculate 5 to the power of 0 and get 1.

$$sort(1+0,25^{-2}-0,5^{-2}-2^{4};\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Calculate 0,25 to the power of -2 and get 16.

$$sort(1+16-0,5^{-2}-2^{4};\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Add 1 and 16 to get 17.

$$sort(17-0,5^{-2}-2^{4};\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Calculate 0,5 to the power of -2 and get 4.

$$sort(17-4-2^{4};\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Subtract 4 from 17 to get 13.

$$sort(13-2^{4};\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Calculate 2 to the power of 4 and get 16.

$$sort(13-16;\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Subtract 16 from 13 to get -3.

$$sort(-3;\left(2^{-1}-1\right)^{-1}+\left(-2\right)^{3})$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$sort(-3;\left(\frac{1}{2}-1\right)^{-1}+\left(-2\right)^{3})$$

Subtract 1 from \frac{1}{2} to get -\frac{1}{2}.

$$sort(-3;\left(-\frac{1}{2}\right)^{-1}+\left(-2\right)^{3})$$

Calculate -\frac{1}{2} to the power of -1 and get -2.

$$sort(-3;-2+\left(-2\right)^{3})$$

Calculate -2 to the power of 3 and get -8.

$$sort(-3;-2-8)$$

Subtract 8 from -2 to get -10.

$$sort(-3;-10)$$

To sort the list, start from a single element -3.

$$-3$$

Insert -10 to the appropriate location in the new list.

$$-10;-3$$

Evaluate

$$-3,\ -10$$