Solve {l}{5+4-3*6div3}{24+144div12*68div34-48}{32div2-5*1+4}

$$\left. \begin{array} { l } { 5 + 4 - 3 \times 6 \div 3 } \\ { 24 + 144 \div 12 \times 68 \div 34 - 48 } \\ { 32 \div 2 - 5 \times 1 + 4 } \end{array} \right.$$

Sort

$$0,3,15$$

Solution Steps

Add 5 and 4 to get 9.

$$sort(9-\frac{3\times 6}{3},24+\frac{\frac{144}{12}\times 68}{34}-48,\frac{32}{2}-5\times 1+4)$$

Cancel out 3 and 3.

$$sort(9-6,24+\frac{\frac{144}{12}\times 68}{34}-48,\frac{32}{2}-5\times 1+4)$$

Subtract 6 from 9 to get 3.

$$sort(3,24+\frac{\frac{144}{12}\times 68}{34}-48,\frac{32}{2}-5\times 1+4)$$

Divide 144 by 12 to get 12.

$$sort(3,24+\frac{12\times 68}{34}-48,\frac{32}{2}-5\times 1+4)$$

Multiply 12 and 68 to get 816.

$$sort(3,24+\frac{816}{34}-48,\frac{32}{2}-5\times 1+4)$$

Divide 816 by 34 to get 24.

$$sort(3,24+24-48,\frac{32}{2}-5\times 1+4)$$

Add 24 and 24 to get 48.

$$sort(3,48-48,\frac{32}{2}-5\times 1+4)$$

Subtract 48 from 48 to get 0.

$$sort(3,0,\frac{32}{2}-5\times 1+4)$$

Divide 32 by 2 to get 16.

$$sort(3,0,16-5\times 1+4)$$

Multiply 5 and 1 to get 5.

$$sort(3,0,16-5+4)$$

Subtract 5 from 16 to get 11.

$$sort(3,0,11+4)$$

Add 11 and 4 to get 15.

$$sort(3,0,15)$$

To sort the list, start from a single element 3.

$$3$$

Insert 0 to the appropriate location in the new list.

$$0,3$$

Insert 15 to the appropriate location in the new list.

$$0,3,15$$

Evaluate

$$3,\ 0,\ 15$$