Solve {l}{5+7/8+2/4+1/3}{-7/8-frac{2}{4}-frac{1}{3}}{-5}

$$\left. \begin{array} { l } { 5 + \frac { 7 } { 8 } + \frac { 2 } { 4 } + \frac { 1 } { 3 } } \\ { - \frac { 7 } { 8 } - \frac { 2 } { 4 } - \frac { 1 } { 3 } } \\ { - 5 } \end{array} \right.$$

Evaluate

$$0$$

Solution Steps

Convert 5 to fraction \frac{40}{8}.

$$\frac{40}{8}+\frac{7}{8}+\frac{2}{4}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Since \frac{40}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.

$$\frac{40+7}{8}+\frac{2}{4}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Add 40 and 7 to get 47.

$$\frac{47}{8}+\frac{2}{4}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{47}{8}+\frac{1}{2}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Least common multiple of 8 and 2 is 8. Convert \frac{47}{8} and \frac{1}{2} to fractions with denominator 8.

$$\frac{47}{8}+\frac{4}{8}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Since \frac{47}{8} and \frac{4}{8} have the same denominator, add them by adding their numerators.

$$\frac{47+4}{8}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Add 47 and 4 to get 51.

$$\frac{51}{8}+\frac{1}{3}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Least common multiple of 8 and 3 is 24. Convert \frac{51}{8} and \frac{1}{3} to fractions with denominator 24.

$$\frac{153}{24}+\frac{8}{24}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Since \frac{153}{24} and \frac{8}{24} have the same denominator, add them by adding their numerators.

$$\frac{153+8}{24}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Add 153 and 8 to get 161.

$$\frac{161}{24}-\frac{7}{8}-\frac{2}{4}-\frac{1}{3}-5$$

Least common multiple of 24 and 8 is 24. Convert \frac{161}{24} and \frac{7}{8} to fractions with denominator 24.

$$\frac{161}{24}-\frac{21}{24}-\frac{2}{4}-\frac{1}{3}-5$$

Since \frac{161}{24} and \frac{21}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{161-21}{24}-\frac{2}{4}-\frac{1}{3}-5$$

Subtract 21 from 161 to get 140.

$$\frac{140}{24}-\frac{2}{4}-\frac{1}{3}-5$$

Reduce the fraction \frac{140}{24} to lowest terms by extracting and canceling out 4.

$$\frac{35}{6}-\frac{2}{4}-\frac{1}{3}-5$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{35}{6}-\frac{1}{2}-\frac{1}{3}-5$$

Least common multiple of 6 and 2 is 6. Convert \frac{35}{6} and \frac{1}{2} to fractions with denominator 6.

$$\frac{35}{6}-\frac{3}{6}-\frac{1}{3}-5$$

Since \frac{35}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{35-3}{6}-\frac{1}{3}-5$$

Subtract 3 from 35 to get 32.

$$\frac{32}{6}-\frac{1}{3}-5$$

Reduce the fraction \frac{32}{6} to lowest terms by extracting and canceling out 2.

$$\frac{16}{3}-\frac{1}{3}-5$$

Since \frac{16}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-1}{3}-5$$

Subtract 1 from 16 to get 15.

$$\frac{15}{3}-5$$

Divide 15 by 3 to get 5.

$$5-5$$

Subtract 5 from 5 to get 0.

$$0$$

Factor

$$0$$