Solve {l}{4x-3y=0}{5y-4=3}

$$\left. \begin{array} { l } { 4 x - 3 y = 0 } \\ { 5 y - 4 = 3 } \end{array} \right.$$

Solve for x, y

$$x = \frac{21}{20} = 1\frac{1}{20} = 1.05$$

$$y = \frac{7}{5} = 1\frac{2}{5} = 1.4$$

Solution Steps

Consider the second equation. Add 4 to both sides.

$$5y=3+4$$

Add 3 and 4 to get 7.

$$5y=7$$

Divide both sides by 5.

$$y=\frac{7}{5}$$

Consider the first equation. Insert the known values of variables into the equation.

$$4x-3\times \frac{7}{5}=0$$

Multiply -3 and \frac{7}{5} to get -\frac{21}{5}.

$$4x-\frac{21}{5}=0$$

Add \frac{21}{5} to both sides. Anything plus zero gives itself.

$$4x=\frac{21}{5}$$

Divide both sides by 4.

$$x=\frac{\frac{21}{5}}{4}$$

Express \frac{\frac{21}{5}}{4} as a single fraction.

$$x=\frac{21}{5\times 4}$$

Multiply 5 and 4 to get 20.

$$x=\frac{21}{20}$$

The system is now solved.

$$x=\frac{21}{20} y=\frac{7}{5}$$